Question

rationalize the denominator of 7 / 3 root 3 minus 2 root 2

Answer 1

Hey friend,
Here is the answer you were looking for:
$\frac{7}{3 \sqrt{3} - 2 \sqrt{2} } \\ \\ on \: rationalizing \: the \: denominator \: we \: get \\ \\ = \frac{7}{3 \sqrt{3} - 2 \sqrt{2} } \times \frac{3 \sqrt{3} + 2 \sqrt{2} }{3 \sqrt{3} + 2 \sqrt{2} } \\ \\ using \: the \: identity \\ (a + b)(a - b) = {a}^{2} - {b}^{2} \\ \\ = \frac{7(3 \sqrt{3} + 2 \sqrt{2} ) }{ {(3 \sqrt{3} )}^{2} - {(2 \sqrt{2} )}^{2} } \\ \\ = \frac{7 \times 3 \sqrt{3} + 7 \times 2 \sqrt{2} }{27 - 8} \\ \\ = \frac{21 \sqrt{3} + 14 \sqrt{2} }{19}$

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@Mahak24

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Answer 2

Answer:

Step-by-step explanation:

7/3√3-2√2 *3√3+2√2/3√3+2√2

=7(3√3+2√2)/27-8

=21√3+14√2/19