rationalize the denominator of each of the following one by root 7 + root 6 minus root 3
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1÷√7+√6-√3
1÷√7×√7÷√7 = √7÷7
then,
√7÷7+√6-√3 = √7+7(√6-√3)÷7
1÷√7×√7÷√7 = √7÷7
then,
√7÷7+√6-√3 = √7+7(√6-√3)÷7
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