Question

rationalize the denominator7/ (5√3 - 5√2)​

Answer 1

7/5√1=,7/5√×5√/5√=7(5√1)/(5√1)^2=35√1/25

Answer 2

Step-by-step explanation:

Hi,

7/(5√3 - 5√2)

Rationalising the denominator (5√3 - 5√2)

7 / ( 5√3 - 5√2 ) × (5√3+5√2)/(5√3+5√2)

7(5√3+5√2)/(5√3-5√2)(5√3+5√2)

35√3+35√2 / (5√3)² - (5√2)² [(a²)-(b²)=(a+b)(a-b)]

35√3+35√2/75 -50

35√3 + 35√2 / 25

5(7√3+7√2)/25

7√3+7√2/5 [ Answer]

Hope it will help you:)