Question

rationalize the denominators of:
$3 \div \sqrt{5}$
$2 \sqrt{3 \div \sqrt{5} }$
$1 \div \sqrt{3 - \sqrt{2} }$
$3 \div \sqrt{5 + \sqrt{2} }$
$\sqrt{3} + 1 \div \sqrt{3 } - 1$

$2 - \sqrt{3 \div 2 + \sqrt{3} }$
$\sqrt{3} - \sqrt{2} \div \sqrt{3} + \sqrt{2}$
$\sqrt{6} - \sqrt{5} \div \sqrt{6} + \sqrt{5}$
$2 \sqrt{5} + 3 \sqrt{2} \div 2 \sqrt{5} - 3 \sqrt{2}$

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Answer 1

Answer:

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