Math, asked by 3765smhs, 3 months ago

Rationalize the denominerer 10upon
3√16 - √2​

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Answered by rajeevr06
0

Answer:

 \frac{10}{3 \sqrt{6} -  \sqrt{2}  }  =  \frac{10}{3 \sqrt{6} -  \sqrt{2}  }  \times  \frac{3 \sqrt{6}  +  \sqrt{2} }{3 \sqrt{6} +  \sqrt{2}  }  =  \\  \frac{10(3 \sqrt{6} +  \sqrt{2} ) }{ {(3 \sqrt{6}) }^{2}  -  {( \sqrt{2}) }^{2} }  =  \\  \frac{10(3 \sqrt{6} +  \sqrt{2} ) }{54 - 2}  =  \\  \frac{5(3 \sqrt{6} +  \sqrt{2})  }{26}  \: ans.

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