Question

rationalize the given fraction


the answer should be in fraction

Answer 1

hope it is helpful for you

Answer 2

hiii!!!

here's Ur answer...

$given \: = > \frac{7 + 3 \sqrt{5} }{3 + \sqrt{5} } \\ \\ = \frac{7 + 3 \sqrt{5} }{3 + \sqrt{5} } \times \frac{3 - \sqrt{5} }{3 - \sqrt{5} } \\ \\ = \frac{(7 + 3 \sqrt{5} )(3 - \sqrt{5}) }{(3 + \sqrt{5} )(3 - \sqrt{5} )} \\ \\ = \frac{7(3 - \sqrt{5}) + 3 \sqrt{5}(3 - \sqrt{5} )}{ {(3)}^{2} - {( \sqrt{5} )}^{2} } \\ \\ = \frac{21 - 7 \sqrt{5} + 9 \sqrt{5} - 3 \sqrt{25} }{9 - 5} \\ \\ = \frac{21 + 2 \sqrt{5} - (3 \times 5)}{4} \\ \\ = \frac{21 - 15 + 2 \sqrt{5} }{4} \\ \\ = \frac{6 + 2 \sqrt{5} }{4} \\ \\ = \frac{3 + \sqrt{5} }{2}$

hope this helps..!!