Tha 7th term of an A.p is 32 and 13th term is 62 .Find the A. P.
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given,
7th term of AP= 32
=> a+ (7-1)d = 32
=> a +6d= 32. ___(1)
and,
13th term of AP= 62
=> a+ (13-1)d = 62
=> a+12d = 62 ___ (2)
eq.(2) - eq(1)
6d = 30
=> d = 5
put d= 5 in equation (1)
we get, a = 2
we know that AP is in the form of a, a+d, a+2d...
so the AP will be:
2, 7, 12, 17...
7th term of AP= 32
=> a+ (7-1)d = 32
=> a +6d= 32. ___(1)
and,
13th term of AP= 62
=> a+ (13-1)d = 62
=> a+12d = 62 ___ (2)
eq.(2) - eq(1)
6d = 30
=> d = 5
put d= 5 in equation (1)
we get, a = 2
we know that AP is in the form of a, a+d, a+2d...
so the AP will be:
2, 7, 12, 17...
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1
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