Question

Rationalizethe denominator of 5/√3-√5

Answer 1

Answer:

5(√3+√5)

Step-by-step explanation:

5/√3-√5

rationalise:

5x√3+√5/(√3-√5)x(√3+√5)

(a+b)(a-b)=a^2-b^2

5√3+5√5/(√3-√5)^2

5√3+5√5/-2

5(√3+√5)/-2

Answer 2

Step-by-step explanation:

$\frac{5}{ \sqrt{3} - \sqrt{5} } \\ = \frac{5}{ \sqrt{3} - \sqrt{5} } \times \frac{ \sqrt{3} + \sqrt{5} }{ \sqrt{3} + \sqrt{5} } \\ = \frac{5 \sqrt{3} + 5 \sqrt{5} }{( \sqrt{3}) ^{2} - ( \sqrt{5} ) ^{2} } \\ = \frac{5 \sqrt{3} + 5 \sqrt{5} }{3 - 5} \\ = \frac{5 \sqrt{3} + 5 \sqrt{5} }{ - 2} \\ = \frac{ - 5 \sqrt{3} - 5 \sqrt{5} }{2}$