Question

rationalizing the denomination of following
please solve this three questions

Answer 1

hereisyouranswerabove

Answer 2

Heya!

Here is yr answer.....

$1) \: \frac{ \sqrt{3} - 1}{ \sqrt{3} + 1 } \\ \\ on \: rationalising \: .......... \\ \\ = > \frac{ \sqrt{3} - 1}{ \sqrt{3} + 1} \times \frac{ \sqrt{3} - 1 }{ \sqrt{3} - 1} \\ \\ = > \frac{ 3 - 2 \sqrt{3} + 1 }{3 - 1} \\ \\ = > \frac{4 - 2 \sqrt{3} }{2} \\ \\ = > \frac{2( 2- \sqrt{3}) }{2} \\ \\ = > 2 - \sqrt{3} \\ \\ \\ 2) \: \frac{ \sqrt{6} }{ \sqrt{5} + \sqrt{2} } \\ \\ on \: rationalising \: \\ \\ = > \frac{ \sqrt{6} }{ \sqrt{5} + \sqrt{2} } \times \frac{ \sqrt{5} - \sqrt{2} }{ \sqrt{5} - \sqrt{2} } \\ \\ = > \frac{ \sqrt{30} - \sqrt{12} }{5 - 2} \\ \\ = > \frac{ \sqrt{30} - \sqrt{12} }{ 3} \\ \\ \\ 3) \: \frac{2 - \sqrt{3} }{2 + \sqrt{3} } \\ \\ on \: rationalising \: ....... \\ \\ = > \frac{2 - \sqrt{3} }{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} } \\ \\ = > \frac{4 - 4 \sqrt{3} + 3}{4 - 3} \\ \\ = > \frac{7 - 4 \sqrt{3} }{ 1} \\ \\ = > 7 -4 \sqrt{3}$

Hope it hlpz..