Question

rationlaise the denominator 1/√8+√3-√11​

Answer 1

Answer:

1/√8+√3-√11.

Rationalising denominator of √8+√3-√11 is √8+√3+√11.

Multiply numerator & denominator by √8+√3+√11.

1/√8+√3-√11×√8+√3+√11/√8+√3+√11.

√8+√3+√11/(√8+√3)²-(√11)² (Because (a-b)×(a+b)=a²-b² where a=√8+√3 & b=√11).

√8+√3+√11/(√8)²+(√3)²+2(√8)(√3)-11. (Because (a+b)²=a²+b²+2ab where a=√8 & b=√3 & √ & ² will cancel).

√8+√3+√11/8+3+2√24-11. (Because √8×√3=√24 & √ & ² will cancel).

√8+√3+√11/11+2√24-11.

√8+√3+√11/2√24. (Because +×-=- so, 11 & -11 will cancel).

I think this is your answer.