Question

RATIONSLISE THE DENOMINATOR 5+ROOT 3/7-4 ROOT 3

Answer 1

denominator becomes 1?

Answer 2

hii!!

here's Ur answer...

$given \: \frac{5 + \sqrt{3} }{7 - 4 \sqrt{3} } \\ \\ = \frac{5 + \sqrt{3} }{7 - 4 \sqrt{3} } \times \frac{7 + 4 \sqrt{3} }{7 + 4 \sqrt{3} } \\ \\ = \frac{(5 + \sqrt{3} )(7 + 4 \sqrt{3}) }{(7 - 4 \sqrt{3} )(7 + 4 \sqrt{3} )} \\ \\ = \frac{5(7 + 4 \sqrt{3} ) + \sqrt{3} (7 + 4 \sqrt{3}) }{ {7}^{2} - {(4 \sqrt{3}) }^{2} } \\ \\ = \frac{35 + 20 \sqrt{3} + 7 \sqrt{3} + (4 \times 3)}{49 - (16 \times 3)} \\ \\ = \frac{35 + 27 \sqrt{3} + 12 }{49 - 48} \\ \\ = 47 + 27 \sqrt{3}$

hope this helps..!!