Question

ratios please answer me dudes.

Answer 1

Given , that x varies inversely as square of ' y ' .

let , x = k / y^2 _______________eq.(1)

here , k is a proportional constant .

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Define K : when ,y = 2 , x = 1
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put value of ' x ' and ' y' in eq. (1) , we get

1 = k / ( 2 )^2

1 = k / 4 => k = 4

put value of ' k ' in eq. (1)

now the equation (1) is

x = 4 / y^2

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Find value of ' x ' for ' y = 6 '
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x = 4 / y^2

x = 4 / ( 6 )^2

x = 4 / 36

x = 1 / 9

therefore , value of x = 1 / 9

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Your Answer : x = 1 / 9
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