Question

Ratuo of frequency of revolution of electron in the 2nd excited state of He+ and 2nd state of hydogen is​

Answer 1

Explanation:

f1/f2 = z13/n12 x n22/z23 [Ratio of frequencies of electron in the second state of He+ to the second state of Hydrogen]

Substituting the values n1= 3, z1 = 2, z2=1 , n2 = 2 we get

f1/f2 = 32/27

Hence option A is the correct answer.

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