Question

Ravi about to mobile phone for rupees 10,000 he sold one at a profit of 10% and the other at a loss of 10% Ravi got the same amount for each mobile find the cost of each mobile phone​

Answer 1

Answer:

☺️☺️

Let x be cost of 1st phone and y be of 2nd

ATQ

x+y=10,000

and also

(110/100)×x=(90/100)×y

=> 11x=9y

=>11x-9y = 0

solving both the equation

we get x= 4,500

and y=5,500