Math, asked by purnasripodila, 1 year ago

ravi bought 30kg tea at rupees 80 perkg and 50kg tea at rupees 50 per kg.he mixed both varieties of tea and sold it at rupees 75 per kg.find his gain or loss percentage

Answers

Answered by singhishita123456789
5

Answer:

Ans : Rs.17.7 per kg

Step-by-step explanation:

Solution 1

Total quantity of the mixture = 35 + 45 = 80 kg

Cost price of this 80 kg mixture = 35×12.50 + 45×16.50 = Rs. 1180

Selling price of 80 kg mixture to earn 20% profit =  

1180×120100=1416

i.e. ,Selling price of 1 kg mixture to earn 20% profit =  

141680=17710=17.7

Solution 2 (using using using rule of alligation)Ratio in which rice 1 and rice 2 are mixed : 35 : 45 = 7 : 9

Let x be the cost price of 1 kg mixture  

By the rule of alligation,

12.5 16.5  x 16.5-x       x-12.5

16.5-x : x-12.5 = 7 : 9

148.5 - 9x = 7x - 87.5

16x = 236 x =  23616 = 594

Required selling price =  594×120100=17710=17.7  per kg

Answered by kavya23908
3

Answer:

Step-by-step explanation:

30X80= 2400. Rs. And for 50X50 = 2500 Rs. total Expense is 2400+2500 = 4900. Now he sold both 80 kg in 75 Rs. so 80X75 = 6000 Rs. so he earn 6000 - 4900 = 1100 Rs. So on for 4900 sales he got 6000 ∴ On 100 Sales ? He got. 6000X 100 ÷ 4900 = 22.4 % he gain.

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