Question

Ravi bought two mobile phones for 10,000. He solel
ata profit of 10% and other at a loss of 10l Davi
got the same amount for each mobile. find the cost
of each mobile phone​

Answer 1

Answer:

rupees 5000 each

Answer 2

Let x be cost of 1st phone and y be of 2nd

Let x be cost of 1st phone and y be of 2ndATQ

Let x be cost of 1st phone and y be of 2ndATQx+y=10,000

Let x be cost of 1st phone and y be of 2ndATQx+y=10,000and also

Let x be cost of 1st phone and y be of 2ndATQx+y=10,000and also(110/100)×x=(90/100)×y

Let x be cost of 1st phone and y be of 2ndATQx+y=10,000and also(110/100)×x=(90/100)×y=> 11x=9y

Let x be cost of 1st phone and y be of 2ndATQx+y=10,000and also(110/100)×x=(90/100)×y=> 11x=9y=>11x-9y = 0

Let x be cost of 1st phone and y be of 2ndATQx+y=10,000and also(110/100)×x=(90/100)×y=> 11x=9y=>11x-9y = 0solving both the equation

Let x be cost of 1st phone and y be of 2ndATQx+y=10,000and also(110/100)×x=(90/100)×y=> 11x=9y=>11x-9y = 0solving both the equation we get x= 4,500

Let x be cost of 1st phone and y be of 2ndATQx+y=10,000and also(110/100)×x=(90/100)×y=> 11x=9y=>11x-9y = 0solving both the equation we get x= 4,500and y=5,500