Ravi bought two mobile phones for ₹10000 .he sold one at the profit of 10% and the other at a loss of 10% .ravi got the same amount for each mobile .find the cost of each mobile phones.
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let x be cost of 1st phone and y be of 2nd
ATQ
x+y=10,000
and also
(110/100)×x=(90/100)×y
=> 11x=9y
=>11x-9y = 0
solving both the equation
we get x= 4,500
and y=5,500
ATQ
x+y=10,000
and also
(110/100)×x=(90/100)×y
=> 11x=9y
=>11x-9y = 0
solving both the equation
we get x= 4,500
and y=5,500
shimranpati05:
ok
u know hindi?
ans in English but i cannot understand middle part pkz ans in explanation
okk
the question is saying that
the price which he got when he sold the mobile in loss is same that he got when sold the other mobile in profit
ok? understood??
if not i can explain more
ok
ok
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