Ravi has 3 times as many two rupee coins as he has five rupee coins. If he has in
seventy-seven rupee coins. How many coins of each denomination does he leave?
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Answer:
Let the no. of 5 rupee coins be X
no. of 2 rupee coins be 3x
Total money =77
ATP,
2 (3x) + 5 (X) = 77
6x + 5x = 77
11x = 77
X = 77/11
X = 7
The no. of 5 rupee coins = 7
The no. of 2 rupee coins = 3×7
=21
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