Question

Ravi has 5 more pencil then meena If both of them have 19
pencils in all . how many pencils does ravi and meena have.​

Answer 1

Given:-

• Ravi has 5 more pencil than Meena.
• The total number of pencils they both have is 19.

To find:-

• The number of pencil Ravi and Meena has.

Solution:-

Let the number of pencil Meena has be "q" pencils.

So, according to the question, the number of pencils Ravi has will be "(q + 5)" as he has 5 pencils more than Meena.

We're also given that the total number of pencils they both have is 19, i.e,

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \underline{ \boxed{ \sf{q + (q + 5) = 19}}}$

Now, by solving the equation formed:

• Removing the brackets-

$\longmapsto{ \sf{q + q + 5 = 19}}$

• Simplifying the LHS-

$\longmapsto{ \sf{2q + 5 = 19}}$

• Transposing the like term from LHS to RHS (plus sign change to minus sign in transposition)-

$\longmapsto{ \sf{2q = 19 - 5}}$

• Simplifying the RHS-

$\longmapsto{ \sf{2q = 14}}$

• Again transposing the like term from LHS to RHS (this time, multiplication sign changes to division)

$\longmapsto{ \sf{q = 14 \div 2}}$

• Simplifying the RHS-

$\longmapsto{ \sf{q = \dfrac{ \cancel{14}}{ \cancel{2}} }} \\ \\ \longmapsto{ \underline{ \underline{ \sf{\pmb{\red{q = 7}}}}}}$

‎

As we know, "q" is the number of pencils Meena has. So, we can say that Meena has 7 pencils and by this, we can calculate the number of pencils Ravi has.

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \longmapsto{ \sf{(q + 5)}} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \longmapsto{ \sf{( {7} + 5)}} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \longmapsto \underline{ \underline{ \tt{ \pmb{12}}}}$

Verification:-

How to verify? It can be done by simply adding the number of pencils Meena and Ravi has, and then checking whether it equals the total number of pencils.

$\longmapsto{ \sf{Ravi + Meena = 19}} \\ \\ \longmapsto{ \sf{12 + 7 = 19}} \\ \\ \longmapsto{ \sf{19 = 19}}$

Since, LHS = RHS, our answer is correct!

$\\ \therefore \underline{ \sf{ \pmb{The \: number \: of \: pencils \: meena \: and \: ravi \: have\: is \: \red{7} \: and \: \red{12 }\: respectively. }}}$

________________________________________

Answer 2

G i v e n:-

• Ravi has 5 more pencil than Meena.
• The total number of pencils they both have is 19.

T o F i n d:-

• The number of pencil Ravi and Meena has.

S o l u t i o n:-

• Let the number of pencil Meena has be "q" pencils.

So, according to the question, the number of pencils Ravi has will be "(q + 5)" as he has 5 pencils more than Meena.

We're also given that the total number of pencils they both have is 19, i.e,

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \underline{ \boxed{ \sf{q + (q + 5) = 19}}}$

Now, by solving the equation formed:

Removing the brackets-

$\longmapsto{ \sf{q + q + 5 = 19}}$

Simplifying the LHS-

$\longmapsto{ \sf{2q + 5 = 19}}$

Transposing the like term from LHS to RHS (plus sign change to minus sign in transposition)-

$\longmapsto{ \sf{2q = 19 - 5}}$

Simplifying the RHS-

$\longmapsto{ \sf{2q = 14}}$

Again transposing the like term from LHS to RHS (this time, multiplication sign changes to division)

$\longmapsto{ \sf{q = 14 \div 2}}$

Simplifying the RHS-

$\longmapsto{ \sf{q = \dfrac{ \cancel{14}}{ \cancel{2}} }} \\ \\ \longmapsto{ \underline{ \underline{ \sf{\pmb{\red{q = 7}}}}}}$

‎

As we know, "q" is the number of pencils Meena has. So, we can say that Meena has 7 pencils and by this, we can calculate the number of pencils Ravi has.

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \longmapsto{ \sf{(q + 5)}} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \longmapsto{ \sf{( {7} + 5)}} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \longmapsto \underline{ \underline{ \tt{ \pmb{12}}}}$

Verification:-

• How to verify? It can be done by simply adding the number of pencils Meena and Ravi has, and then checking whether it equals the total number of pencils.

$\longmapsto{ \sf{Ravi + Meena = 19}} \\ \\ \longmapsto{ \sf{12 + 7 = 19}} \\ \\ \longmapsto{ \sf{19 = 19}}$

Since, LHS = RHS, our answer is correct!

$\\ \therefore \underline{ \sf{ \pmb{The \: number \: of \: pencils \: meena \: and \: ravi \: have\: is \: \red{7} \: and \: \red{12 }\: respectively. }}}$

________________________________________