Question

Ravi is now 6 years older than Neeta. Three years ago he was twice as old as she was then. Find their present ages​

Answer 1

$\Large{\textbf{\underline{\underline{According\:to\:the\:Question}}}}$

Assumption

Age of Ravi be p

Also,

Age of Neeta be y

So,

p = y + 6 .... (1)

Also,

p - 3 = (y - 3) × 2

p - 3 = 2y - 6

p - 2y = -6 + 3

p - 2y = -3

Now,

From Equation (1) we have

(y + 6) - 2y = -3

y + 6 - 2y = -3

-y + 6 = -3

-y = -3 - 6

-y = -9

y = 9

Hence we get,

p = 9 + 6

p = 15

Age of Ravi is 15 also Age of Neeta is 9

Answer 2

Step-by-step explanation:

Let the present age of Neeta be x years.

Then, the present age of Ravi (x+6) years

Three years ago

• The age of Neeta = (x-3) years
• The age of Ravi = (x+6-3) = (x+3) years

Atq,

$\implies x + 3 = 2(x -3 ) \\ \implies x + 3 = 2x - 6 \\ \implies 3 + 6 = 2x - x \\ \implies 9 = x \\ \implies x = 9$

Hence,

• The age of Neeta = 9 years
• The age of Ravi =(9+6) years = 15 years