Question

Ravi is twice as old as his son. sixteen years ago, he was six times as old as his son. find their present ages​

Answer 1

Step-by-step explanation:

Let the present ages of father and son be x and y, respectively.

As per the problem, six years ago,

As per the problem, six years ago,(x−6)=3(y−6)

Six years later, (x+6)=2(y+6)

Solving these two equations, we get father's age is 42 years, and son's age is 18 years.

(x−6). = 3(y−6)

Answer 2

Let the present age of the son be x. Let the present age of the father be 2x.

When you say 6 times his son’s age, I’m assuming it means his son’s age 20 years ago.

The age of the son 20 years ago is x-20 and the age of the father is 2x-20.

So, 2x-20=6(x-20)

Solving this linear equation, we get 4x=100 or x=25.

Hence, the present age of the son is 25 years while the age of the father is 50 years.

You can check this. 20 years ago, age of the son was 5 years while age of the father was 30 years. 30 is 6 times 5. Hence, the answer obtained is correct!