Question

Ravi scored 30 percent marks and failed by 15 marks. Deepak scored 40 percent marks and obtained 35 marks more than those required to pass. Find the minimum percent pass marks.​

Answer 1

Answer:

Let the maximum marks =x

∴ pass marks=30% of x+15=40% of x -35

⇒

100

30x

+15=

100

40x

−35

⇒

100

40x

−

100

30x

=35+15

⇒

100

10x

=50

⇒x=500

∴Required pass number=

100

30

×500+15=165

Pass Percentage=

500

165

×100=33%

Answer 2

$\huge\underbrace{\bf{☆SoLuTion:}}$

Let's

The Maximum Mark be 'x'

Ravi: To get pass mark = 30% of x + 15

Deepak: To get pass mark = 40% of x - 35

Then,

Pass Mark => 30% of x + 15 = 40% of x -35

➝ $\frac {30x}{100}+15 = \frac{40x}{100}-35$

➝ $\frac {40x}{100}-\frac{30x}{100} = 35+15$

➝ $10x = 50×100$

➝ $x = \frac{5000}{10}$

$→\; x = 500$

Maximum Mark Is 500

Pass Mark = $\frac{30}{100}×500+15$

=> $150+15$

=> $165$

Pass Mark Percentage

$→\;\frac{165}{500}×100$

$→\;\frac{160}{5}$

$☞\;33$%

$\pink{\underline{\underline{\bf{Required\;AnSweR:}}}}$

The Minimum Mark Percentage is $\fbox\red{\sf{33}}$%

Hope It Helps You ✌️