ravi wants to cross a wide road.At what angle with the edge of the road should he walk so that he walks the shortest distance
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Answer:
90° as perpendicular is always the shortest distance
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Hence ravi should walk at 90 deg angle to edge of road to cross the road with shortest distance
Step-by-step explanation:
Let say Ravi walk at an angle of α
and distance covered = d
Then Horizontal distance = d Cosα
& Vertical distance = d sinα
d sinα = w = width of road
=> d²sin²α = w²
d² = d²Cos²α + d²sin²α
d² = d²cos²α + w²
as w² is constant ( width of road)
hence to minimize d² ,
d²cos²α should be minimum
d²cos²α = 0
=> cos²α = 0
=> cosα = 0
=> α = 90°
Hence ravi should walk at 90 deg angle to edge of road to cross the road with shortest distance
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