Ravish sold his motorcycle to Vineet at a loss of 28%. Vineet spent rs. 1680 on its repairs and sold the motorcycle to Rahul for rs. 35910, there by making a profit of 12.5"%, Find the cost price of the motorcycle for ravish.
Answers
Answer:
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Step-by-step explanation:
Let us consider the cost price of motorcycle for Ravish be Rs x
Loss% for Ravish = 28%
Selling price for Ravish = x – x × 28/100
= (100x – 28x)/100 = 72x/100
= Rs 18x/25
Selling price for Ravish = cost price for Vineet = Rs 18x/25
Repair cost by Vineet = Rs 1680
Total cost price of the motorcycle for Vineet = Rs18x/25 + Rs 1680
Selling price for Vineet = Rs 35910
Profit = 35910 – (18x+42000)/25 = Rs (855750 – 18x)/25
Profit % = 12.5% (Given)
By using the formula,
Gain % = (gain/cost price) × 100
=> [(855750-18x)/25] / [(18x+42000)/25] × 100 = 12.5
=> [(855750-18x)/25] × [25/(18x+42000)] = 125/1000
=> (855750-18x) / (18x+42000) = 1/8 => By cross multiplying we get
=> 8(855750-18x) = (18x+42000) => 6846000 – 144x = 18x + 42000
=> 6846000 – 42000 = 18x + 144x
=> 162x = 6804000 x = 6804000/162 = 42000
∴ Cost price of motorcycle for Ravish = Rs 42000
I hope it helps you