Question

Ray of light incident at an angle 50° is refracted through a Prism of minimum deviation. the angle of prism is 60°. find the angle of minimum deviation and refractive index of the prism​

Answer 1

Answer:

I hope ot helps you.....

Answer 2

Answer:

4.41

Explanation:

Angle of minimum deviation-Angle of minimum deviation is equal to the angle of prism A of an equilateral glass prism. The angle of incidence at which minimum deviation will be obtained is.

Refractive index-The refractive index determines how much the path of light is bent, or refracted, when entering a material. This is described by Snell's law of refraction,$n1 sin θ1 = n2 sin θ2$, where θ1 and θ2 are the angle of incidence and angle of refraction, respectively, of a ray crossing the interface between two media with refractive indices n1 and n2. The refractive indices also determine the amount of light that is reflected when reaching the interface, as well as the critical angle for total internal reflection, their intensity (Fresnel's equations) and Brewster's angle.

In the case of minimum deviation, ∠r

Solving way-

$delm=r1+r2$

$r1=r2=r$

$delm=2r$

$r=delm/2$

put value $delm=40$

Now put the formula and get the answer 4.41

For more refers to-

https://brainly.in/question/8443273?referrer=searchResults

https://brainly.in/question/6544289?referrer=searchResults

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