Question

Re = radius of earth
Rm = radius of moon

R e/ Rm = ?​

Answer 1

$\huge \color{green} \underline \red{answer}$

$acceleration \: due \: to \: graity \: = g = \frac{Gm}{ {r}^{2} }$

$\bold{me = pe \times \frac{4}{3} \pi {</strong><strong>R</strong><strong>}^{3} } \\ \bold{mm = pm \times \frac{4}{3} \pi {</strong><strong>R</strong><strong>}</strong><strong>^{3} } \\ \implies \frac{ge}{</strong><strong>G</strong><strong>m} = \frac{ \frac{</strong><strong>G</strong><strong>me}{ {</strong><strong>R</strong><strong>}^{2} } }{ \frac{</strong><strong>G</strong><strong>mm}{ {</strong><strong>R</strong><strong>}^{2} } }$

$\implies \frac{ge}{gm} = \frac{</strong><strong>peR</strong><strong>}{</strong><strong>pmR</strong><strong>}$

$so \: answer \: is.. \\ \frac{peR}{pmR}$

Answer 2

r

r 2

r 2

r 2 Gm

r 2 Gm

me=pe×

me=pe× 3

me=pe× 34

me=pe× 34

me=pe× 34 πR

me=pe× 34 πR 3

me=pe× 34 πR 3

me=pe× 34 πR 3 mm=pm×

me=pe× 34 πR 3 mm=pm× 3

me=pe× 34 πR 3 mm=pm× 34

me=pe× 34 πR 3 mm=pm× 34

me=pe× 34 πR 3 mm=pm× 34 πR

me=pe× 34 πR 3 mm=pm× 34 πR 3

me=pe× 34 πR 3 mm=pm× 34 πR 3

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gm

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge =

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme \implies \frac{ge}{gm} = \frac{peR}{pmR}⟹

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme \implies \frac{ge}{gm} = \frac{peR}{pmR}⟹ gm

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme \implies \frac{ge}{gm} = \frac{peR}{pmR}⟹ gmge

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme \implies \frac{ge}{gm} = \frac{peR}{pmR}⟹ gmge

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme \implies \frac{ge}{gm} = \frac{peR}{pmR}⟹ gmge =

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme \implies \frac{ge}{gm} = \frac{peR}{pmR}⟹ gmge = pmR

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme \implies \frac{ge}{gm} = \frac{peR}{pmR}⟹ gmge = pmRpeR

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme \implies \frac{ge}{gm} = \frac{peR}{pmR}⟹ gmge = pmRpeR

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme \implies \frac{ge}{gm} = \frac{peR}{pmR}⟹ gmge = pmRpeR

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme \implies \frac{ge}{gm} = \frac{peR}{pmR}⟹ gmge = pmRpeR soansweris..

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme \implies \frac{ge}{gm} = \frac{peR}{pmR}⟹ gmge = pmRpeR soansweris..pmR

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme \implies \frac{ge}{gm} = \frac{peR}{pmR}⟹ gmge = pmRpeR soansweris..pmRpeR

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme \implies \frac{ge}{gm} = \frac{peR}{pmR}⟹ gmge = pmRpeR soansweris..pmRpeR

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme \implies \frac{ge}{gm} = \frac{peR}{pmR}⟹ gmge = pmRpeR soansweris..pmRpeR

me=pe× 34 πR 3 mm=pm× 34 πR 3 ⟹ Gmge = R 2 Gmm R 2 Gme \implies \frac{ge}{gm} = \frac{peR}{pmR}⟹ gmge = pmRpeR soansweris..pmRpeR