reaction between 2c(h2)15 and o2
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Answered by
4
Answer:
Explanation:
You have listed entropy changes for the reaction. In fact, these are values for
Δ
H
∘
reaction
H
C
≡
C
H
+
5
2
O
2
→
2
C
O
2
+
H
2
O
;
Δ
H
∘
reaction
=
−
1299.6
⋅
k
J
⋅
m
o
l
−
1
(
i
)
C
+
O
2
→
C
O
2
;
Δ
H
∘
reaction
=
−
393.5
⋅
k
J
⋅
m
o
l
−
1
(
i
i
)
H
2
+
1
2
O
2
→
H
2
O
;
Δ
H
∘
reaction
=
−
285.6
⋅
k
J
⋅
m
o
l
−
1
(
i
i
i
)
We want
Δ
H
∘
for:
2
C
+
H
2
→
H
C
≡
C
H
;
Δ
H
∘
=
?
?
If I do the sum of the given reactions in this manner,
2
×
(
i
i
)
−
(
i
)
+
(
i
i
i
)
, I get the following:
2
C
+
2
O
2
+
2
C
O
2
+
H
2
O
+
H
2
+
1
2
O
2
→
2
C
O
2
+
H
C
≡
C
H
+
H
2
O
+
5
2
O
2
Which after cancelling gives:
2
C
(
s
)
+
H
2
(
g
)
→
H
C
≡
C
H
(
g
)
Δ
H
∘
reaction
=
227
⋅
k
J
⋅
m
o
l
−
1
Note here that
Δ
H
∘
reaction
=
Δ
H
∘
f
acetylene
.
So here we have used the thermochemical equations as linear equations to give us the equation that we sought (and thus necessarily the thermodynamic parameters).
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