Reaction between calcium carbide and bromoethane (two molecules) leads to formation of
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Bromoethane and an aqueous solution of sodium hydroxide. Calcium carbide reacts with water to form calcium hydroxide (slaked lime). When ethene reacts with water, it forms ethyl alcohol as a product. When ethyl bromide reacts with NaOH, it follows SN2 mechanism to form ethyl alcohol
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Bromoethane and an aqueous solution of sodium hydroxide. Calcium carbide reacts with water to form calcium hydroxide (slaked lime).
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