Reaction is a second order with respect to reactant how is rate affected if concentration is reduced to one fourth
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Here's what you were looking for:
When the concentration of the reactant is reduced to one fourth the rate of rxn will be 1/16th time the initial value.
Initially
r=[A]^2
Finally
r'=[A/4]^2
Therefore r' = r/16
Hope this clears your doubt.✌️
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Kindly mark the answer as brainliest if you find it useful.
Here's what you were looking for:
When the concentration of the reactant is reduced to one fourth the rate of rxn will be 1/16th time the initial value.
Initially
r=[A]^2
Finally
r'=[A/4]^2
Therefore r' = r/16
Hope this clears your doubt.✌️
DO FOLLOW ME FOR MORE SUCH QUALITY ANSWERS.
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