Question

reaction of propanone with methylmagnesium bromide ...and name the final product formed...

Answer 1

HOPE IT HELPS YOU..............

Answer 2

Answer:

The final product formed is 2-Methyl-propan-2-ol by the reaction of a methyl magnesium bromide with propanone followed by hydrolysis.

Explanation:

Propanone is a ketone with three carbons and one ketone group. This reacts with the methyl magnesium bromide which is a Grignard reagent, it is an organometallic chemical reaction in which alkyl, allyl, aryl- etc magnesium halides (Grignard reagent) are added to a carbonyl group (a ketone or aldehyde) to form tertiary or secondary alcohol when followed by the hydrolysis.

Here, a ketone, propanone reacts with the methyl magnesium bromide (Grignard reagent) to form 2-Methyl-propan-2-ol when, the reaction is followed by hydrolysis.

The complete reaction is:

#SPJ3