Question

Reaction to produce tungsten metal from tungsten(VI) oxide:
___WO3(s) + ___3H2(g) = ___W(s) + ___3_H2O(l)

Answer 1

Explanation:

WO3 + 3H2---> W + 3H2O

Mass of WO3= 56.9g

Mass of W= 41.4g

Molar mass of WO3= 232g/mol

Molar mass of W= 184g/mol

From the balanced equation,

234g of WO3 gives 184g of W

56.9g of WO3 should give 184/232 x 56.9= 45.1g

Now, since only 41.4g of W is produced,

Percentage yield= 41.4/45.1 x 100 = 91.8%