Math, asked by princess5368, 2 months ago

read each problem carefully and solve as required then answer the questions that follow.​

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Answers

Answered by tennetiraj86
18

Step-by-step explanation:

1)X+Y=6 and 3X+Y=10

2) No. of jeans =2

No. of blouses =4

3)Given system of linear equations in two variables are consistent and independent or Intersecting lines

Explanation:-

Given equations are

X+Y=6

=>X+Y-6=0

we have a1=1; b1=1; C1=-6

and

3X+Y=10

=>3X+Y-10=0

we have a2=3;b2=1;C2=-10

now

a1/a2=1/3

b1/b2=1/1=1

C1/C2=-6/-10=3/5

a1/a2b1/b2≠c1/c2

Given system of linear equations in two variables are consistent and independent or Intersecting lines

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Answered by mathdude500
2

Answer:

Answer 1.

\bf \:300x + 100y = 1000

\bf \:x + y = 6

where,

  • x = number of jeans purchased
  • y = number of blouses purchased be 'y'.

Answer 2.

\bf \:2 \:  jeans \:  and  \: 4  \: blouses \:  are \:  purchased.

Answer 3.

Let us consider 2 linear equations

\bf \:a_1x + b_1y + c_1 = 0  \:and  \: a_2x + b_2y + c_2 = 0

then

1. System of equation is consistent and independent iff

\bf \:\dfrac{a_1}{a_2} ≠\dfrac{b_1}{b_2}

2. System of equation is consistent and dependent iff

\bf \:\dfrac{a_1}{a_2}  = \dfrac{b_1}{b_2}  = \dfrac{c_1}{c_2}

3. System of equation is inconsistent iff

\bf \:\dfrac{a_1}{a_2}  = \dfrac{b_1}{b_2}  ≠ \dfrac{c_1}{c_2}

The solution of given equations is consistent and independent.

Step-by-step explanation:

Let number of jeans purchased be 'x' and number of blouses purchased be 'y'.

Case 1.

The cost price of 1 jean is Php 300 and cost price of 1 blose is Php 100. Total amount spend is Php 1000.

\bf\implies \:300x + 100y = 1000....(1)

Case 2.

Total number of jeans and blouse purchased is 6.

\bf\implies \:x + y = 6

\bf\implies \:y = 6 - x.....(2)

On substituting the value of y from (2) to (1), we get

\bf\implies \:300x + 100(6 - x) = 1000

\bf\implies \:300x + 600 - 100x = 1000

\bf\implies \:200x = 1000 - 600

\bf\implies \:200x = 400

\bf\implies \:x = 2

Put x = 2, in equation (2), we get

\bf\implies \:y = 6 - 2 = 4

So, it means 2 jeans and 4 blouses are purchased.

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