Question

Read the question in the picture .

Answer 1

Step-by-step explanation:

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first term = 15

common ratio = -2

third term

a+2d = third term

15+2(-2) = 15-4 = 11

hope it helps uh

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Answer 2

Answer:

3rd option

60

Note:

★ A sequence in which the ratio between the consecutive terms are equal is called Geometric progression (GP) or geometric sequence .

★ The general term of a GP is given by ;

a(n) or T(n) = a•r^(n - 1)

★ The general form of a GP is ;

a , ar , ar² , ar³ .....

Solution:

Given : a1 = a = 15 , r = -2

To find : T(3) = ?

We have ;

1st term , a1 or a = 15

Also,

Common ratio , r = -2

Now,

We know that ,

T(n) = a•r^(n - 1)

Thus,

=> T(3) = a•r^(3 - 1)

=> T(3) = a•r²

=> T(3) = 15•(-2)²

=> T(3) = 15•4

=> T(3) = 60

Hence,

Third term = 60