reciprocal of root 3 +root 2
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Answer:
taking a rational number i.e., 2 and subtracting from it. As a result, we get ( - √3 ) which is an irrational number. Hence, the reciprocal of ( 2 + √3 ) is an irrational number.
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Reciprocal of root 3 =1/√3
1/√3+√2=1+√6/√3
=1+√6(√3)/√3(√3) (Rationalising)
=√3+√2x3(√3)/3
=√3+3√2/3
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