Rectangle ABCD is formed in a circle as shown in figure. If AE = 8 cm
and AD = 5 cm, find the perimeter of the rectangle
Answers
The perimeter of rectangle is 34cm.
AE = 8 cm (Given)
AD = 5 cm (Given)
Let the Radius be = DE
DE = AE + AD
= 8 + 15 = 13
Thus, DB = AC = 13 ( As diagonals of the rectangel are equal )
In right ADC
AC² = AD² + DC²
13² = 5² + DC
169 = 25 + DC
DC² = 169 - 25
DC² = 144
DC = √144
DC = 12
Perimeter of rectangle ABCD = 2 ( AD + DC)
= 2 ( 5 + 12)
= 2 × 17
= 34
Thus, the perimeter of rectangle is 34cm.
Perimeter of rectangle = 34 cm
Step-by-step explanation:
Missing figure attached:
AE = 8 cm
AD = 5 cm
DE = AD + AE
=> DE = 13 cm
DE = Radius
DB = Radius
=> DB = DE = 13 cm
DB = AC ( diagonals of rectangle)
AC² = AD² + CD²
=> 13² = 5² + CD²
=> CD = 12
Perimeter of rectangle = 2(5 + 12)
= 34 cm
Learn more:
the perimeter of a semicircular protractor with diameter 10cm ...
https://brainly.in/question/13217507
if perimeter of the two similar triangles are the in the ratio 5 : 4 then ...
https://brainly.in/question/7633761
