Question

Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2, 1)A(2,1)A, left parenthesis, 2, comma, 1, right parenthesis, B(5, 1)B(5,1)B, left parenthesis, 5, comma, 1, right parenthesis, C(5, 6)C(5,6)C, left parenthesis, 5, comma, 6, right parenthesis, and D(2, 6)D(2,6)D, left parenthesis, 2, comma, 6, right parenthesis.
Given these coordinates, what is the length of side ABABA, B of this rectangle?

Answer 1

Answer:

Length of Side AB = 3 unit

Step-by-step explanation:

Rectangle ABCD

A = ( 2 , 1)

B = (5 , 1)

C = (5 , 6)

D = (2 , 6)

AB = $\sqrt{(5-2)^2 + (1-1)^2}$

=> AB = $\sqrt{3^2 + 0^2}$

=> AB = $\sqrt{9 + 0}$

=> AB = √9

=> AB = 3

Length of Side AB = 3 unit

CD = 3 BC = 5 , AD = 5

Area of rectangle = 3 * 5 = 15 sq unit

Answer 2

Answer:

13 units

Step-by-step explanation: