Question

rectangle has length 3 cm greater than its width. If it has an area of 28 cm 2 , find the dimensions of the rectangle.

Answer 1

Answer:

The dimensions of the rectangle are 7 cm × 4 cm.

Step-by-step explanation:

Let,

Breadth of the rectangle (l) = x

Length of the rectangle (b) = x + 3

Area of the rectangle = 28 cm²

Area of the rectangle = l × b

⇒ (x) × (x + 3) = 28

⇒ x² + 3x = 28

⇒ x² - 3x - 28 = 0

⇒ x² - 7x + 4x - 28 = 0

⇒ (x - 7) + 4(x - 7) = 0

⇒ (x - 7)(x + 4) = 0

⇒ x = 4

Breadth = 4 cm

Length -

⇒ 4 + 3

⇒ 7 cm

The dimensions of the rectangle are 7 cm × 4 cm.

Answer 2

✿Question✿

rectangle has length 3 cm greater than its width. If it has an area of 28 cm 2 , find the dimensions of the rectangle.

✿Answer✿

according to Question:-

• breadth of the rectangle=x
• Length of the rectangle=x+3
• Area of the reactangle=28cm²

$\bf \huge \bigstar \: area \: \: of \: \: the \: \: reactangle \: \: = l \times b$

$\sf \implies \: (x) \times (x + 3) = 28 \\ \\ \sf \implies \: {x}^{2} + 3x = 28 \\ \\ \sf \implies \: {x}^{2} - 3x - 28 = 0 \\ \\ \sf \implies \: {x}^{2} - 7x + 4x - 28 = 0 \\ \\ \sf \implies \:x(x - 7) + 4(x - 7) = 0 \\ \\ \sf \implies \:(x - 7)(x + 4) = 0 \\ \\ \therefore \: \tt \: breadth \: \: = 4\: \: cm \\ \\ \therefore \tt \: length = 4 + 3 = 7 \: cm$

Dimensions of the reactangle are 7 cm and 4 cm...