Question

Rectangular Area of dimension 16 15 feet under each basketball loop need to be colord by different paint. How much Will be the cost of painting at rate of rupees 1.75/sq.feet?

Answer 1

The total cost is Rs. 840.

Explanation:

Given,

Length(l) = 94 feet and breadth(b) = 50 feet

Area of basketball loop = $94\times 50=4700 ft^{2}$

There are two teams and each team have 5 players.

∴ Total number of player = 2 × 5 = 10

Area covered by each player = $\dfrac{4700}{10} =470 ft^{2}$

∴ Number of wooden panel = $\dfrac{Area of court}{Area of wooden panel}$

∴ Total area = 2 × 16 × 15 = 480 $ft^{2}$

Hence, the total cost = 480 × 1.75 = Rs. 840.