rectangular coil having a length cm
breadth room is kept in a uniform
magnetic field of 2x10-5 wblime the coil
carries a current of 100 miliampere
compute the torque aching on conductor
of a length isomwhen it is in a
peopendicular magnetic field
given: L=15cm b= loom magnitude.....
Answers
Answer:
Given Information:
- Length = 15 cm
- Breadth = 10 cm
- Magnetic Field = 2 × 10⁻⁵ Wb
- Current = 100 mA
According to Electromagnetism, the torque experienced in a Magnetic Field is given by the expression:
⇒ Torque = M × B [ Cross Product ]
where, M and B are Magnetic Moment and Magnetic Field Vectors respectively.
Also, Magnetic Moment is given by the formula:
⇒ M = I.A
where, I is the current flowing and A is the Area Vector of the current carrying conductor.
Therefore the final formula is given as:
⇒ Torque = (I.A) × B
Now we need to calculate the Area from the given information.
Area of rectangular loop = Length × Breadth
⇒ Area = 15 cm × 10 cm = 150 cm² = 0.015 m²
Substituting all the values in the formula we get,
⇒ Torque = 0.015 m² × 0.1 A × 2 × 10⁻⁵ Wb
⇒ Torque = 0.003 × 10⁻⁵
⇒ Torque = 3 × 10⁻⁸ N/m
Answer:
3 × 10^-8 N/m.
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