Question

Rectangular field is 16 meters long and 10 meters
wide. There is a path of equal width all around it,
having an area of 120 sq. meters. Find the width of
the path.​

Answer 1

Answer:

The width of  the path is 2 m.​

Step-by-step explanation:

Answer 2

Let x be the width

Length of inner rectangle = 16m

" " outer. " I6+2x

breadth of inner rectangle = 10m

breadth of outer. " lO+2x

Area of the path=

Area of outer rectangle-Area of

inner rectangle

=(I 6+2x)(l0+2x) - 160=120

= 160+20 x+32x+4x2-160=120

4x2 +52x -120=0

x 2+l3x-30= 0

x2 +15x-2x-30=0

x(x+15)-2(x +15) = 0

(x-2)(x+15)=0

x=2

width=2m. Ans