Question

rectangular piece of a paper 22 cm x 26 cm is folded without overlapping to make a cylinder of height 6 cm find the volume of the cylinder​

Answer 1

In this question , Height of the cylinder = 6 cm.
And , Circumference of the base = 22 cm
So, 2*22/7*r = 22.
i.e. r = 7/2 cm.
Apply the formula of volume of cylinder = 22/7*r^2*h
i.e. 22/7 * 7/2 * 7/2* 6 cubic cm = 231 cubic cm.

HOPE IT HELPS!!!

Answer 2

Answer:

The volume of the cylinder is $231 \: cm {}^{3}$

Step-by-step explanation:

Clearly, the length of the given rectangle is the perimeter of the base of the given cylinder and the breadth of the rectangle is the height of the cylinder.

∴ height = 6 cm ⇒h = 6 cm.

Let r be the radius of its base.

Then, $2\pi \: r \: = 22 \: cm$

⇒$2 \times \frac{22}{7} \times r = 22 \: cm$

⇒$r = \frac{7}{2} \: cm$

∴ volume of the cylinder = $\pi \: r {}^{2}h \: cubic \: units$

= $( \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \times 6) \: cm {}^{2}$

= $231 {}^{3}$

Hence, the volume of the cylinder is $231 {}^{3}$