reduce in normal form x-√y+8=0
Answers
Answered by
1
x -√y+8 = 0
x+8 = √y
y=(x +8)square
y = x square +16x +64
x+8 = √y
y=(x +8)square
y = x square +16x +64
bpss1:
arent we suppose to reduce it in the form..
Xcos w +Ysin w=p
Similar questions