reduce the equation 2x-7y+3=0 to the intercept form and hence find the intercepts on the axes
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Answered by
1
5xy+3=0
5xy=0-3
5xy=0
xy=0/5
Answered by
3
you have to change the number dear ...
The given equation is 9x+7y−3=0
⇒9x+7y=3$$
Dividing both sides by 3, we get
⇒
3
9x
+
3
7y
=1
⇒
3
1
x
+
7
3
y
=1 which is the required intercept form.
Here x−intercept=a=
3
1
and x−intercept=b=
7
3
∴The length of the segment intercepted between the axes=
a
2
+b
2
=
(
3
1
)
2
+(
7
3
)
2
=
9
1
+
49
9
=
9×49
49+81
=
3×7
130
=
21
130
units
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