Question

Reduce the following to its
simplest form using laws of boolean
algebra : A.B'+A'.B.C'+(A.C)'+B.C​

Answer 1

Answer:

ab'+a'bc'+a'+c'+bc              ((ac)'=a'+c' demorgon law)

=ab'+a'+bc+c'                   (a'bc'+c'=c' absorption law)

=(a+a')(b'+a')+(b+c')(c+c')

=b'+a'+b+c'

=a'+c'

Answer 2

Answer:

A.B'+A'.B.C'+(A.C)'+B.C

→A.B'+A'.B.C'+A.+C'+B.C

→A.B'+A'(B.C'+1)+C'+B.C

→A.B'+A'+C'+B.C

→(A+A')(A'+B')+(C'+B)(C'+C) [A+BC=(A+B)(A+C)]

→1.(A'+B')+(B+C').1 [A'+A=1]

→A'+B'+B+C'

→A'+C'+1

→(A'+1)+C'

→1+C'

→1 ANSWER.