Reduce the line 2x - 3y + 5 = 0 in slope - intercept , and normal forms .
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Solution :-. y = 2x /3 + 5/3 ,
tan¢ = m = 2/3 , c = 5/3
intercept form :
x/(-5/2) + y / (5/3) = 1
a = - 5/2 , b = 5/3
normal , -2x/√13 + 3y /√13 = 5/√13
sin@ = 3/13 , cos@ = 2/√13 , p = 5/√13
tan¢ = m = 2/3 , c = 5/3
intercept form :
x/(-5/2) + y / (5/3) = 1
a = - 5/2 , b = 5/3
normal , -2x/√13 + 3y /√13 = 5/√13
sin@ = 3/13 , cos@ = 2/√13 , p = 5/√13
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