Question

Reema Swims in a pool that is 100 m wide.she covers 200 m 'in 10 minutes by Swimming in one direction and then swiming back
along the same path. Calculate her average speed and Velocity
​

Answer 1

Answer :-

→ Reema's average speed = 0.3 m/s

→ Reema's average velocity = 0 m/s

Explanation :-

We have :-

• Width of the pool = 100 m

• Distance covered by Reema = 200 m

• Time taken = 10 mins = 600 sec

________________________________

For average speed :-

= Total distance/Total time

= 200/600

= 2/6

= 0.3 m/s

For average velocity :-

In the above case, the initial and final points of Reema are same. So, her displacement will be zero.

So, her average velocity :

= Total displacement/Total time

= 0/600

= 0 m/s

Answer 2

Given:-

• Width of the pool is 100m wide

• Reema Covers = 200 m

• Time taken to cover 200m = 10mins

To Find:-

• Her average Speed and Velocity

Formula used:-

• ${\boxed{Speed=\dfrac{Distance}{Time}}}$

• ${\boxed{Velocity=\dfrac{Displacement}{Time}}}$

Solution:-

Firstly,

• Time = 10mins = 10 × 60sec = 600sec

Now,

$:\implies\: Average\:Speed=\dfrac{Distance}{Time}$

$:\implies\: Average\:Speed=\dfrac{200}{600}$

$:\implies\: Average\:Speed=\dfrac{2}{6}$

${\boxed{:\implies\: Average\:Speed=0.3m/s}}$

And,

As we know, Reema's initial and final points of are same. So, displacement = 0.

$:\implies\: Average\:Velocity=\dfrac{Displacement}{Time}$

$:\implies\: Average\:Velocity=\dfrac{0}{600}$

${\boxed{:\implies\: Average\:Velocity=0m/s}}$

Hence, her Average speed and Velocity is 0.3m/s and 0m/s respectively.

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