Biology, asked by dhrubajyotichakrabor, 9 days ago

Reema took 5ml of Lead Nitrate solution in a beaker and added approximately 4ml of Potassium lodide solution to it. What would she observe? A. The solution turned red. B. Yellow precipitate was formed. C. White precipitate was formed. D. The reaction mixture became hot.​

Answers

Answered by rohitmerdas12
0

Answer:

this is due to exothermic reaction ok

Answered by Anonymous
4

B. Yellow precipitate was formed is the correct observation.

  • The reaction between lead nitrate and potassium iodide results in production of aqueous solution of potassium nitrate and precipitate of lead iodide.
  • Lead iodide precipitate is yellow in colour and hence this will be observed.
  • Moreover, the reaction is endothermic and hence can not become hot.
  • This reaction is double displacement reaction.
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