Question

reenɑ is 20 yeɑr younger to her mother. ɑfter 10 Yeɑrs her mother will be twice ɑs old ɑs reenɑ will be then. how old is reenɑ now?

❥ησ cσρy
❥ɴᴏ sᴘᴀᴍ
❥ᴅᴏɴ'ᴛ ʙᴇ ɢʀᴇᴇᴅʏ ғᴏʀ ᴘᴏɪɴᴛ
​

Answer 1

Answer:

The answer Reena's present age = 10 years

Step-by-step explanation:

=> Let Reena present age be x years.

=> Hence, her mother present age = ( x + 20 )

[ As reena is 20 years younger, her mother age is 20 years more than her age ]

=> After 10 years,

=> Reena age will be = ( x + 10 ) years

and her mother age will be [ ( x + 20 ) + 10 ] years

=> According to the problem,

=> Reena mother will be 2 times as old as Reena after 10 year.

=> ( x + 20 ) + 10 = 2 ( x + 10 )

=> x + 20 + 10 = 2x + 20

=> x + 30 = 2x + 30

=> 2x + 20 = x + 30

=> 2x = x + 30 - 20

=> 2x = x + 10

=> 2x - x = 10

=> x = 10

:- Reena present age is 10 years.

Check :- Reena present age = 10 years

Reena mother age = 30 years

After 10 years, Reena age = 10 + 10 = 20 years

After 10 years, mother age = 30 + 10 = 40 years and 40 is twice of 20

Thus, the answer Reena present age = 10 years is correct.

I hope this will help you dear..

Always stay safe and stay healthy..

Answer 2

$\sf {(x+20)+10=2(x+10)} \\ \sf \to {x+20+10=2x+20} \\ \sf \to {x+30=2x+30} \\ \sf \to 2x=x+10 \\ \sf \to 2x-x=10 \\ \sf \to x=10 \\ \sf \therefore {Reena \:present \:age=10\:years}$

Answer 3

$\sf {(x+20)+10=2(x+10)} \\ \sf \to {x+20+10=2x+20} \\ \sf \to {x+30=2x+30} \\ \sf \to 2x=x+10 \\ \sf \to 2x-x=10 \\ \sf \to x=10 \\ \sf \therefore {Reena \:present \:age=10\:years}$