Question

Reena is 6 years older than his brother ajay. If the sum of their ages be 28 years. Find their present ages?

Answer 1

reena's age=6+x
let ajay's age=x

ATQ

reena's age+ajay's age=28
6+x+x=28
2x=22
x=11

therefore ajay=x=11yrs

reena=x+6=11+6=17 yrs

Answer 2

Answer:

Step-by-step explanation:

Let the age of Ajay be 'x' and age of Reena be '6x' .

According to condition,

6x + x = 28

7x= 28

x= 28/7

x= 4

So,

Ajay's age is 4 years.

Reena's age = 6x = 6×4 = 24 years.

Therefore, present age of Ajay is 4 years and present age of Reena is 24 years.

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