Question

Reena went shopping and spent half of what she had on buying fruits. Out of
the money she was left with, she gave H 5 to a beggar. She spent one-third of
the remaining money on rickshaw fare. When she reached home, she found
that she has exactly H 100 left. How much money she initially had? What value
is shown by Reena?

Answer 1

Answer:

Reena initially had 310 Rs.

Step-by-step explanation:

let Reena has x rupees in the beginning.

out of those she spend half on fruits.

●Money spend on fruits=x/2 rupees

●She has left with x/2 rupees

●After giving 5 Rs to beggar,

●money left with Reena = (x/2-5)Rs

●Spend 1/3 on the rickshaw

●money left with Reena

●\begin{gathered} (\frac{x}{2} - 5) - \frac{1}{3}

●(\frac{x}{2} - 5) \\ \\ = \frac{2}{3} (\frac{x}{2} - 5) \:

●\end{gathered}(2x−5)−31(2x−5)=32(2x−5)

Now she has Rs 100,i.e.

●\begin{gathered} \frac{2}{3} (\frac{x}{2} - 5) = 100 \\

●\\ (\frac{x}{2} - 5) = 150 \\ \\ \frac{x}{2} = 155 \\ \\ x =

●310 \\ \\ \end{gathered}32(2x−5)=100(2x−5)=1502x

=155x=310

●She has 310 Rupees with her.

●Reena is kind hearted lady,that's why she gave money to beggar.

■Note: Value based questions are removed from board exams■

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